Soils, Syncopations, Solitude

Monday, March 31, 2008

Knight Farmer.


Pop Quiz:
Assume that the sprinkler clock is 1 hour, thirty minutes slow. If the sprinkler needs to reach 117" to complete the round, and the degrees are increasing, at what time (PM) should lobiwan return to shut down the sprinkler? (H/R stands for hours/revolution.)

Here is the view from the motor last night. From left to right, you can see my house lights, followed by my parents' yard light, followed by my pickup lights which are illuminating the sprinkler.

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7 Comments:

Blogger Ben said...

11:19pm

[{(work shown here...)}]
1) current photo time 20:30 shown plus 1.5hrs provided by proctor = 10pm actual at time of photo;
2) 64 hours for 360 degrees = 5.6 degrees of revolution per hour;
3) 117 target - 109.6 current = 7.4 degrees of revolution required to reach 117 degrees;
4) 7.4 / 5.6 = 1.32 hours or revolution
5) 1.32 hours is roughly 79 minutes;
6) 79 minutes added to 10pm is...

1:05 PM, March 31, 2008

 
Blogger betsyann said...

I looked at the math problem and thought happily "Not my problem!!"

1:46 PM, March 31, 2008

 
Blogger Ben said...

the more i look at that last photo the more i think it would be an award winner if the resolution was higher

it's the kind of photo that leads to contemplation

9:08 AM, April 01, 2008

 
Blogger tara said...

I'm with Betsy on this one - so glad my life doesn't not involve life like this!!! Also wanted to say thanks for the lovely captions as of late!

9:59 PM, April 01, 2008

 
Blogger lobiwan said...

Ben--I guess I forgot to mention that you are not allowed to show your work, or use a pencil, and only use the calculator on you cell phone.
Unfortunately the original photograph, while at a very nice resolution, is very grainy. I guess I need to start taking a tripod with me everywhere I go so I can take prettier night shots...

betsyann and tara-- math will find you, whether you like it or not.

8:36 AM, April 02, 2008

 
Blogger Ben said...

then i say figure in your head 5 degrees per hour and use that as your standard all the time so there's no calcs in the middle of the night...

and yes, i was thinking, "he's out there, prolly in 6 inches of mud and water dripping on his head, wondering what time to come back, can i answer with a guesstimate?" but i didn't have the frame of reference for the pop quiz, so i went formal

1:03 PM, April 02, 2008

 
Blogger lobiwan said...

Now you are assuming that the sprinkler is always applying 0.80".

11:19 PM, April 02, 2008

 

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